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	<title>Comments for Rhapsody in Numbers</title>
	<atom:link href="http://yozh.org/comments/feed/" rel="self" type="application/rss+xml" />
	<link>http://yozh.org</link>
	<description>Explorations of mathematical beauty and the aesthetic of the abstract.</description>
	<lastBuildDate>Tue, 24 Jan 2012 17:36:29 +0000</lastBuildDate>
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		<title>Comment on The Collatz Fractal by Xander</title>
		<link>http://yozh.org/2012/01/12/the_collatz_fractal/#comment-519</link>
		<dc:creator>Xander</dc:creator>
		<pubDate>Tue, 24 Jan 2012 17:36:29 +0000</pubDate>
		<guid isPermaLink="false">http://yozh.org/?p=1962#comment-519</guid>
		<description>The general goal was to get a smooth function that behaved in a particular manner over the integers.  Since [latex]i\sin(\pi z)[/latex] vanishes over the integers, we can get the behaviour that we want, i.e. [latex]C(x)&#124;_{\mathbb{Z}} = f(x)[/latex] if we drop it.  It was sloppy of me to not go over those details.  Sorry.

Alternatively, I suppose that we could do a better job of choosing the characteristic functions in the first place.  [latex]cos(\pi z/2) = \pm 1[/latex] when [latex]z[/latex] is even, and 0 otherwise; and [latex]\sin(\pi z/2) = \pm 1[/latex] when [latex]z[/latex] is odd, and 0 otherwise.  Squaring these gives us the behaviour we want for the characteristic functions, and application of the power reducing formulae will give us the formula I originally gave.

The morals of the story:  first, the smooth extensions of functions to larger domains need not be unique; and second, I shouldn&#039;t try to work from three sets of notes at the same time.

Thanks for keeping me honest,
xander</description>
		<content:encoded><![CDATA[<p>The general goal was to get a smooth function that behaved in a particular manner over the integers.  Since [latex]i\sin(\pi z)[/latex] vanishes over the integers, we can get the behaviour that we want, i.e. [latex]C(x)|_{\mathbb{Z}} = f(x)[/latex] if we drop it.  It was sloppy of me to not go over those details.  Sorry.</p>
<p>Alternatively, I suppose that we could do a better job of choosing the characteristic functions in the first place.  [latex]cos(\pi z/2) = \pm 1[/latex] when [latex]z[/latex] is even, and 0 otherwise; and [latex]\sin(\pi z/2) = \pm 1[/latex] when [latex]z[/latex] is odd, and 0 otherwise.  Squaring these gives us the behaviour we want for the characteristic functions, and application of the power reducing formulae will give us the formula I originally gave.</p>
<p>The morals of the story:  first, the smooth extensions of functions to larger domains need not be unique; and second, I shouldn&#8217;t try to work from three sets of notes at the same time.</p>
<p>Thanks for keeping me honest,<br />
xander</p>
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	<item>
		<title>Comment on The Collatz Fractal by Jason Liszka</title>
		<link>http://yozh.org/2012/01/12/the_collatz_fractal/#comment-516</link>
		<dc:creator>Jason Liszka</dc:creator>
		<pubDate>Tue, 24 Jan 2012 05:27:44 +0000</pubDate>
		<guid isPermaLink="false">http://yozh.org/?p=1962#comment-516</guid>
		<description>Also, I could only get
C(z) = 1/4 * (2 + 7z - (2 + 5z) cos (pi *z))
from 
C(z) = (-1^z + 1)/2 * (z / 2) – (-1^z – 1)/2 * (3*z + 1)
if I let -1^z = cos (pi * z). But -1^z = cos (pi * z) - i sin (pi * z).

cos(pi*z) behaves the same on positive integers as -1^z, so I guess the choice is arbitrary. I was just a little confused by the derivation. Using -1^z I get a different fractal that diverges almost everywhere.

Great post! Fun thinking about this.</description>
		<content:encoded><![CDATA[<p>Also, I could only get<br />
C(z) = 1/4 * (2 + 7z &#8211; (2 + 5z) cos (pi *z))<br />
from<br />
C(z) = (-1^z + 1)/2 * (z / 2) – (-1^z – 1)/2 * (3*z + 1)<br />
if I let -1^z = cos (pi * z). But -1^z = cos (pi * z) &#8211; i sin (pi * z).</p>
<p>cos(pi*z) behaves the same on positive integers as -1^z, so I guess the choice is arbitrary. I was just a little confused by the derivation. Using -1^z I get a different fractal that diverges almost everywhere.</p>
<p>Great post! Fun thinking about this.</p>
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	<item>
		<title>Comment on The Collatz Fractal by Xander</title>
		<link>http://yozh.org/2012/01/12/the_collatz_fractal/#comment-512</link>
		<dc:creator>Xander</dc:creator>
		<pubDate>Mon, 23 Jan 2012 15:12:28 +0000</pubDate>
		<guid isPermaLink="false">http://yozh.org/?p=1962#comment-512</guid>
		<description>You are correct.  My nemesis, the dreaded WRONG SIGN has reared his ugly head once again.  I have corrected the post.

Thank you,
xander</description>
		<content:encoded><![CDATA[<p>You are correct.  My nemesis, the dreaded WRONG SIGN has reared his ugly head once again.  I have corrected the post.</p>
<p>Thank you,<br />
xander</p>
]]></content:encoded>
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	<item>
		<title>Comment on The Collatz Fractal by Jason Liszka</title>
		<link>http://yozh.org/2012/01/12/the_collatz_fractal/#comment-510</link>
		<dc:creator>Jason Liszka</dc:creator>
		<pubDate>Mon, 23 Jan 2012 01:43:34 +0000</pubDate>
		<guid isPermaLink="false">http://yozh.org/?p=1962#comment-510</guid>
		<description>Interesting! I tried to replicate this and noticed you have a sign error in your first definition of C(z).  You have
C(z) = (-1^z + 1)/2 * (z / 2) + (-1^z - 1)/2 * (3*z + 1)
but I think it should be
C(z) = (-1^z + 1)/2 * (z / 2) - (-1^z - 1)/2 * (3*z + 1).
With the first definition, C(5) = -16 and C^n(i) diverges very rapidly. With the second definition, C(5) = 16 and C^n(i) diverges, but not quite so dramatically.</description>
		<content:encoded><![CDATA[<p>Interesting! I tried to replicate this and noticed you have a sign error in your first definition of C(z).  You have<br />
C(z) = (-1^z + 1)/2 * (z / 2) + (-1^z &#8211; 1)/2 * (3*z + 1)<br />
but I think it should be<br />
C(z) = (-1^z + 1)/2 * (z / 2) &#8211; (-1^z &#8211; 1)/2 * (3*z + 1).<br />
With the first definition, C(5) = -16 and C^n(i) diverges very rapidly. With the second definition, C(5) = 16 and C^n(i) diverges, but not quite so dramatically.</p>
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	<item>
		<title>Comment on Spider&#8217;s Web by Carrie</title>
		<link>http://yozh.org/2012/01/17/spiders_web/#comment-506</link>
		<dc:creator>Carrie</dc:creator>
		<pubDate>Thu, 19 Jan 2012 22:40:07 +0000</pubDate>
		<guid isPermaLink="false">http://yozh.org/?p=2000#comment-506</guid>
		<description>Perfect subject for the prompt :) It almost felt like the narration of a documentary, I could see the spider crafting her web, strand by gooey strand</description>
		<content:encoded><![CDATA[<p>Perfect subject for the prompt :) It almost felt like the narration of a documentary, I could see the spider crafting her web, strand by gooey strand</p>
]]></content:encoded>
	</item>
	<item>
		<title>Comment on A Typical Morning by Xander</title>
		<link>http://yozh.org/2011/12/09/a-typical_morning/#comment-473</link>
		<dc:creator>Xander</dc:creator>
		<pubDate>Tue, 13 Dec 2011 16:05:19 +0000</pubDate>
		<guid isPermaLink="false">http://yozh.org/?p=1925#comment-473</guid>
		<description>Suzanne:  The dog is fine.  She and Katja are getting along very well.

xander</description>
		<content:encoded><![CDATA[<p>Suzanne:  The dog is fine.  She and Katja are getting along very well.</p>
<p>xander</p>
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	<item>
		<title>Comment on A Typical Morning by Tom Nixon</title>
		<link>http://yozh.org/2011/12/09/a-typical_morning/#comment-470</link>
		<dc:creator>Tom Nixon</dc:creator>
		<pubDate>Mon, 12 Dec 2011 23:21:06 +0000</pubDate>
		<guid isPermaLink="false">http://yozh.org/?p=1925#comment-470</guid>
		<description>It&#039;s always nice to have a reminder of why I did not procreate (even though I admit to going through the motions several times).  Me + offspring would = a severely irrational me.  Keep up the good work (somebody&#039;s gotta do it). With love to you both, great-Uncle Tom (cabin optional).</description>
		<content:encoded><![CDATA[<p>It&#8217;s always nice to have a reminder of why I did not procreate (even though I admit to going through the motions several times).  Me + offspring would = a severely irrational me.  Keep up the good work (somebody&#8217;s gotta do it). With love to you both, great-Uncle Tom (cabin optional).</p>
]]></content:encoded>
	</item>
	<item>
		<title>Comment on A Typical Morning by Suzanne Henderson</title>
		<link>http://yozh.org/2011/12/09/a-typical_morning/#comment-465</link>
		<dc:creator>Suzanne Henderson</dc:creator>
		<pubDate>Mon, 12 Dec 2011 07:16:04 +0000</pubDate>
		<guid isPermaLink="false">http://yozh.org/?p=1925#comment-465</guid>
		<description>Xander, You are very funny and of course I noticed that Katja always comes first and that is the way it is.  I am so happy for your new family.  How is the doggy by the way?
Auntie, Suzanne</description>
		<content:encoded><![CDATA[<p>Xander, You are very funny and of course I noticed that Katja always comes first and that is the way it is.  I am so happy for your new family.  How is the doggy by the way?<br />
Auntie, Suzanne</p>
]]></content:encoded>
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	<item>
		<title>Comment on A Typical Morning by Xander</title>
		<link>http://yozh.org/2011/12/09/a-typical_morning/#comment-462</link>
		<dc:creator>Xander</dc:creator>
		<pubDate>Sat, 10 Dec 2011 17:13:56 +0000</pubDate>
		<guid isPermaLink="false">http://yozh.org/?p=1925#comment-462</guid>
		<description>She&#039;s in the office with me right now, &quot;helping&quot; with my topology.  ;)

xander</description>
		<content:encoded><![CDATA[<p>She&#8217;s in the office with me right now, &#8220;helping&#8221; with my topology.  ;)</p>
<p>xander</p>
]]></content:encoded>
	</item>
	<item>
		<title>Comment on A Typical Morning by Supermaren</title>
		<link>http://yozh.org/2011/12/09/a-typical_morning/#comment-461</link>
		<dc:creator>Supermaren</dc:creator>
		<pubDate>Sat, 10 Dec 2011 01:47:10 +0000</pubDate>
		<guid isPermaLink="false">http://yozh.org/?p=1925#comment-461</guid>
		<description>She&#039;ll be helping you out with those proofs in no time. Just you wait.</description>
		<content:encoded><![CDATA[<p>She&#8217;ll be helping you out with those proofs in no time. Just you wait.</p>
]]></content:encoded>
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